Question

Мальчик массой 25 кг со скоростью 0,2 м/с прыгает на санки движущиеся со скоростью 2 м/с и массой 3 кг . С какой скоростью будут двигаться санки с мальчиком?

Answer 1

M1v1+m2v2=v(m1+m2) (Импульс)
v=(m1v1+m2v2)/(m1+m2)=(25*0.2+3*2)/28=0.39 м/с
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Удачи!

Answer 2

Calculation of the Final Velocity of the Sled with the Boy

To calculate the final velocity of the sled with the boy, we can use the principle of conservation of momentum. According to this principle, the total momentum before the jump is equal to the total momentum after the jump.

The momentum of an object is calculated by multiplying its mass by its velocity. Let's denote the mass of the boy as m1 (25 kg) and the mass of the sled as m2 (3 kg). The initial velocity of the boy is v1 (0.2 m/s), and the velocity of the sled is v2 (2 m/s).

Using the conservation of momentum, we can write the equation:

m1 * v1 + m2 * v2 = (m1 + m2) * vf

where vf is the final velocity of the sled with the boy.

Substituting the given values:

25 kg * 0.2 m/s + 3 kg * 2 m/s = (25 kg + 3 kg) * vf

Simplifying the equation:

5 kg m/s + 6 kg m/s = 28 kg * vf

11 kg m/s = 28 kg * vf

Now, we can solve for vf:

vf = (11 kg m/s) / (28 kg) = 0.3929 m/s

Therefore, the sled with the boy will move with a final velocity of approximately 0.3929 m/s.

Please note that the above calculation assumes an idealized scenario without considering factors such as friction or air resistance.