Question

На рисунке 12.8 представлена схема электрической цепи с тремя одинаковыми резисторами R1, R2, R3. В резисторе R1 выделяется мощность электрического тока 6 Вт. Чему равна мощность электрического тока в резисторе R3? Рисунка нет, но я могу описать. Постоянный ток, ключ, резисторы R2 и R3 подключённые параллельно и резистор R1 последовательно. Помогите пажалуйста, заранее спасибо))

Answer 1

Ток через R1 равен I1 и расссеиваемая мощность P1=I1²*R1. Токи через R2  R3 равны и составляют 0,5*I1 (R1=R2-R3). Мощность на R3 равна P3=(0,5*I1)²*R1=0,25*I1²*R1, то есть равна 0,25*P1. Зачем идёт речь про ключ - не понял, коммутаций никаких нет.

Answer 2

Electrical Circuit Analysis

In the given electrical circuit, three identical resistors R1, R2, and R3 are present. Resistor R1 dissipates 6 watts of power. The circuit configuration consists of a constant current source, a switch, and resistors R2 and R3 connected in parallel, while resistor R1 is connected in series.

Power Dissipation in Resistor R3

The power dissipated in a resistor can be calculated using the formula: P = I^2 * R, where P is the power in watts, I is the current in amperes, and R is the resistance in ohms.

Given that resistor R1 dissipates 6 watts of power, we can calculate the current flowing through it using the power formula. Then, we can use the same current value to calculate the power dissipated in resistor R3, as they are in parallel and have the same voltage across them.

Calculation

Using the power formula, we can calculate the current flowing through resistor R1: P = I^2 * R 6 = I^2 * R1

Now, we can calculate the current flowing through resistor R1: I = sqrt(6 / R1)

Next, we can use the same current value to calculate the power dissipated in resistor R3: P = I^2 * R3

Conclusion

The power dissipated in resistor R3 can be calculated using the current value obtained from the power dissipation in resistor R1. This will provide the power dissipated in resistor R3 in the given electrical circuit.