Question

Шарик бросили вертикально вверх с нач. скоростью 10м/с. Найти максимальную высоту на которую поднимется мячик?

Answer 1

36 км/ч=10 м/с.
H= v v - vнач vнач/2g.
H=0-100/-20=5 (м).

Answer 2

Calculation of the Maximum Height

To find the maximum height reached by the ball when thrown vertically upwards with an initial velocity of 10 m/s, we can use the equations of motion. The key equation we will use is:

v^2 = u^2 + 2as

Where: - v is the final velocity (which is 0 m/s at the maximum height) - u is the initial velocity (10 m/s) - a is the acceleration due to gravity (-9.8 m/s^2, considering the direction) - s is the displacement (the maximum height we want to find)

Rearranging the equation, we have:

s = (v^2 - u^2) / (2a)

Substituting the values, we get:

s = (0^2 - 10^2) / (2 * -9.8)

Simplifying the equation, we find:

s = 1.02 meters

Therefore, the maximum height reached by the ball is approximately 1.02 meters.