Question

Определить частоту излучения, кванты которого обладают импульсом 6,62*10^-28 H*c

Answer 1

Дано  P=6,62*10^-28 н*с     ню  -  ?

P= h*ню/С
ню= P*C/h=6,62*10^-28*3*10^8/6,63*10^-34=3*10*10^14 Гц 
Ответ  ню=3*10^14  Гц

Answer 2

Calculating the Frequency of Radiation

To determine the frequency of radiation, we can use the formula:

E = h * f

Where: - E = energy of the radiation - h = Planck's constant (6.62 x 10^-34 J·s) - f = frequency of the radiation

Given the impulse (momentum) of the radiation as 6.62 x 10^-28 H·c, we can use this information to calculate the frequency.

Calculation

Using the given impulse (momentum) of the radiation:

6.62 x 10^-28 H·c = h * f

We can solve for the frequency (f):

f = (6.62 x 10^-28) / h

Result

By substituting the values, we get:

f ≈ (6.62 x 10^-28) / (6.62 x 10^-34) f ≈ 10^6 Hz

Therefore, the frequency of the radiation is approximately 10^6 Hz.

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