Question

Плоский обруч двигаясь без проскальзывания горизонтально с постоянной скоростью прошел за 1 мин расстояние 15 м,с какой частотой вращается обруч если его радиус 30 см? срочно!!!

Answer 1

v=n/t
t= 60 c
s = 15m 
r= 30 cm = 0.3 m
v- частота -?
l = 2Пr= 2*3.14*0.3=1.884 m
n= s/l= 15/1.884= 7.96
v=7.96/ 60=0.133 Гц
отв: v = 0.133 Гц

Answer 2

Calculating the Frequency of Rotation for the Hoop

To calculate the frequency of rotation for the hoop, we can use the formula:

Frequency (f) = Speed (v) / Circumference (C)

Where: - Speed (v) = Distance / Time - Circumference (C) = 2 * π * Radius

Given: - Distance = 15 m - Time = 1 min = 60 seconds - Radius = 30 cm = 0.3 m

First, let's calculate the speed using the given distance and time: Speed (v) = Distance / Time

Speed (v) = 15 m / 60 s = 0.25 m/s

Now, let's calculate the circumference using the given radius: Circumference (C) = 2 * π * Radius

Circumference (C) = 2 * 3.14 * 0.3 m = 1.88 m

Now, we can calculate the frequency of rotation using the formula: Frequency (f) = Speed (v) / Circumference (C)

Frequency (f) = 0.25 m/s / 1.88 m ≈ 0.133 Hz

So, the frequency of rotation for the hoop is approximately 0.133 Hz.