Question

Очень срочно! Даю много баллов! Скоростной лифт массой 1,6 т. поднимается в течение 30 с. Сила тока, потребляемая двигателем, равна 50 А. Напряжение в сети 400 В. КПД двигателя 80 % 1. Сколько электроэнергии затрачено на подъем? 2. На какую высоту поднялся лифт.

Answer 1

Значит так, по порядку: 1)N=IU=50 А * 400 В=20 кВт;
N*t=20 кВт* 30 с=600 кДж;
2) A=N*t*n=600 кДж*0.8=480 кДж;
    h=A/(mg)=480 000 Дж/(1600 кг* 10 м/с^2)=30м.

Answer 2

Calculation of Electrical Energy Consumed

To calculate the electrical energy consumed during the elevator's ascent, we can use the formula:

Electrical Energy (E) = Power (P) x Time (t)

The power consumed by the elevator's motor can be calculated using the formula:

Power (P) = Voltage (V) x Current (I)

Given: - Mass of the elevator (m) = 1.6 t = 1600 kg - Time taken for ascent (t) = 30 s - Current (I) = 50 A - Voltage (V) = 400 V - Efficiency (η) = 80% = 0.8

Let's calculate the electrical energy consumed:

1. Calculate the power consumed by the motor: - Power (P) = Voltage (V) x Current (I) - Power (P) = 400 V x 50 A = 20,000 W

2. Calculate the electrical energy consumed: - Electrical Energy (E) = Power (P) x Time (t) - Electrical Energy (E) = 20,000 W x 30 s = 600,000 J

Therefore, the electrical energy consumed during the elevator's ascent is 600,000 Joules.