Question

Резистори, опир яких становиться 2 ком та 3 ком видповидно соеденены паралельно та подключены до джерела струму постоянной напруге 15 В. Найдите силу тока через каждый з резисторов та опир круга.

Answer 1

Ток в каждом резисторе по закону Ома
I1=U/R1=15/2000=7.5 мА
I2=U/R2=15/3000=5 мА
I=I1+I2=5+7,5=12,5 мА
Rob=U/I=15/12.5*10^-3=1.25 кОм

Answer 2

Calculation of Current through Each Resistor

To find the current through each resistor, we need to apply Ohm's Law, which states that the current flowing through a resistor is equal to the voltage across the resistor divided by its resistance.

Given: - Two resistors, R1 and R2, connected in parallel. - A constant voltage source of 15 V.

We need to find the current through each resistor and the total resistance of the circuit.

Calculation Steps:

1. Calculate the total resistance of the parallel resistors using the formula:

1/R_total = 1/R1 + 1/R2

Let's assume the resistance values for R1 and R2 are 2 Ω and 3 Ω, respectively.

Substituting the values:

1/R_total = 1/2 + 1/3

1/R_total = 3/6 + 2/6

1/R_total = 5/6

R_total = 6/5 Ω

Therefore, the total resistance of the circuit is 6/5 Ω.

2. Calculate the current through each resistor using Ohm's Law:

I = V/R

For R1:

I1 = 15 V / 2 Ω

I1 = 7.5 A

For R2:

I2 = 15 V / 3 Ω

I2 = 5 A

Therefore, the current through R1 is 7.5 A, and the current through R2 is 5 A.

Answer:

The current through each resistor in the circuit is as follows: - The current through resistor R1 is 7.5 A. - The current through resistor R2 is 5 A.

Please note that the total resistance of the circuit is 6/5 Ω.