Вопрос задан 04.05.2019 в 07:51. Предмет Физика. Спрашивает Скороход Валерия.

Помогите пожалуйста!Мимо рабочего равномерно и прямолинейно со скоростью v = 2 м/с движется тележка

массой М = 95 кг. В тот момент, когда тележка поравнялась с рабочим, он положил на нее ящик массой m = 5 кг. Какое количество теплоты выделилось в этом процессе?
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Отвечает Набатов Миша.
Дано:
m1=95 кг;
m2=5 кг;
v1=2 м/c;
v2=0 м/c;
Найти:
Q
Решение:
K1+K2=(m1+m2)*V^2/2+Q;
p=m1*v1=190 кг*м/c;
p=(m1+m2)*v;
v=p/m1+m2=1,9 м/c;
K1=m1v1^2/2=190 Дж;
K2=0,т.к тело не движется.
190=180,5+Q;
Q=9,5 Дж.
Ответ:9,5 Дж.
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculation of Heat Released

To calculate the amount of heat released in this process, we can use the formula:

Q = m * c * ΔT

Where: - Q is the amount of heat released - m is the mass of the object - c is the specific heat capacity of the material - ΔT is the change in temperature

In this case, the heat released will be equal to the heat gained by the object, which can be calculated using the formula:

Q = m * c * ΔT

Let's calculate the heat released step by step:

1. Calculate the initial kinetic energy of the cart before the box is placed on it. - The kinetic energy formula is KE = 0.5 * m * v^2, where m is the mass and v is the velocity. - Substituting the given values, we have KE = 0.5 * 95 kg * (2 m/s)^2. - Calculating this, we find that the initial kinetic energy of the cart is 190 J.

2. Calculate the final kinetic energy of the cart and box system after the box is placed on it. - The final velocity of the cart and box system can be calculated using the principle of conservation of momentum. - Since the cart and box system is initially at rest, the momentum before and after the box is placed on it is conserved. - Therefore, m_cart * v_cart = (m_cart + m_box) * v_final, where m_cart is the mass of the cart, m_box is the mass of the box, and v_final is the final velocity of the cart and box system. - Substituting the given values, we have 95 kg * 2 m/s = (95 kg + 5 kg) * v_final. - Solving for v_final, we find that the final velocity of the cart and box system is 1.9 m/s.

3. Calculate the change in kinetic energy of the cart and box system. - The change in kinetic energy can be calculated using the formula ΔKE = 0.5 * (m_cart + m_box) * (v_final^2 - v^2). - Substituting the given values, we have ΔKE = 0.5 * (95 kg + 5 kg) * ((1.9 m/s)^2 - (2 m/s)^2). - Calculating this, we find that the change in kinetic energy of the cart and box system is -19 J.

4. Calculate the amount of heat released. - Since the change in kinetic energy is negative, it means that the system has lost energy in the form of heat. - Therefore, the amount of heat released is equal to the absolute value of the change in kinetic energy. - Thus, the amount of heat released in this process is 19 J.

Please note that the specific heat capacity of the materials involved (the cart and the box) is not provided in the question. To calculate the exact amount of heat released, we would need this information.

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