Question

Тело массой 2кг свободно падает в течении 6 с. Определите кинетическую энергию тела в конце падения.

Answer 1

V=g*t=10*6=60 м/с
Ek=m*V^2/2=2*60^2/2=3600 Дж

Answer 2

Calculation of Kinetic Energy

To calculate the kinetic energy of an object, we can use the formula:

Kinetic Energy (KE) = 1/2 * mass * velocity^2

In this case, we are given that the mass of the object is 2 kg and it falls freely for 6 seconds. We need to determine the kinetic energy of the object at the end of the fall.

To calculate the velocity of the object at the end of the fall, we can use the equation of motion:

Final Velocity (v) = Initial Velocity (u) + Acceleration (a) * Time (t)

Since the object is falling freely, the initial velocity (u) is 0 m/s and the acceleration (a) is equal to the acceleration due to gravity, which is approximately 9.8 m/s^2.

Substituting the values into the equation, we have:

Final Velocity (v) = 0 + 9.8 * 6

Now, we can calculate the kinetic energy using the formula mentioned earlier:

Kinetic Energy (KE) = 1/2 * mass * velocity^2

Substituting the values, we have:

Kinetic Energy (KE) = 1/2 * 2 * (9.8 * 6)^2

Let's calculate the result.

Calculation:

Final Velocity (v) = 0 + 9.8 * 6 = 58.8 m/s

Kinetic Energy (KE) = 1/2 * 2 * (58.8)^2 = 1/2 * 2 * 3456.64 = 3456.64 J

Therefore, the kinetic energy of the object at the end of the fall is 3456.64 Joules.

Please note that the above calculation assumes that there is no air resistance and the object falls freely under the influence of gravity.