
Club два проводника сопротивлением 40 ом и 10 ом соединены параллельно напряжение в цепи 120 Вольт
Найдите общее сопротивление общую силу тока в цепи и силу тока в каждом проводнике и дети 74

Ответы на вопрос

По закону Ома по каждому проводнику течёт ток I=U/R;
I1=U/R1; I1=120/40=3 А.
I2=U/R2; I2=120/10=12 А.
Общий ток равен сумме всех токов. I=I1+I2; I=3+12=15 А.
Общее сопротивление равно R=U/I; R= 120/15=8 Ом.






Calculation of Total Resistance:
To find the total resistance of the circuit, we need to calculate the equivalent resistance of the two resistors connected in parallel. The formula for calculating the equivalent resistance of two resistors in parallel is:1/R_total = 1/R1 + 1/R2
Given that the resistance of one conductor is 40 ohms (R1) and the resistance of the other conductor is 10 ohms (R2), we can substitute these values into the formula:
1/R_total = 1/40 + 1/10
Simplifying the equation:
1/R_total = (1 + 4)/40
1/R_total = 5/40
1/R_total = 1/8
Therefore, the total resistance (R_total) of the circuit is 8 ohms.
Calculation of Total Current:
To find the total current in the circuit, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R). The formula is:I = V/R_total
Given that the voltage in the circuit is 120 volts and the total resistance is 8 ohms, we can substitute these values into the formula:
I = 120/8
Simplifying the equation:
I = 15 amperes
Therefore, the total current (I) flowing through the circuit is 15 amperes.
Calculation of Current in Each Conductor:
Since the two conductors are connected in parallel, the current splits between them. The current flowing through each conductor can be calculated using the formula:I_conductor = (V/R_conductor)
For the conductor with a resistance of 40 ohms (R1):
I_conductor1 = 120/40
Simplifying the equation:
I_conductor1 = 3 amperes
For the conductor with a resistance of 10 ohms (R2):
I_conductor2 = 120/10
Simplifying the equation:
I_conductor2 = 12 amperes
Therefore, the current flowing through the conductor with a resistance of 40 ohms is 3 amperes, and the current flowing through the conductor with a resistance of 10 ohms is 12 amperes.
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