Question

Расстояние от Луну до Земли 380 тыс км от нее совершая один оборот за 27,3 суток. Вычислети центростремительное ускорение Луны...

Answer 1

s=380000 км=3,8*10⁸ м

T=27,3 суток≈2,4*10⁶ с

a=?

 

a=(2π/T)²*r

a=4π²r/T²

a=4*3,14²*3,8*10⁸/(2,4*10⁶)²

a=39,4384*3,8*10⁸/(5,76*10¹²)

a≈2,6*10⁻³ м/с²

 

Answer 2

Calculating the Centripetal Acceleration of the Moon

The distance from the Moon to the Earth is approximately 384,000 kilometers, and it completes one orbit around the Earth in about 27.3 days.

To calculate the centripetal acceleration of the Moon, we can use the formula:

Centripetal acceleration (a) = v^2 / r

Where: - v = velocity of the Moon in its orbit - r = radius of the Moon's orbit

Velocity of the Moon

The velocity of the Moon in its orbit can be calculated using the formula:

Velocity (v) = 2 * π * r / T

Where: - r = radius of the Moon's orbit - T = time period for one orbit

Using the given values: - r = 384,000 km - T = 27.3 days

Converting the time period to seconds: - 27.3 days * 24 hours/day * 60 minutes/hour * 60 seconds/minute = 2,360,320 seconds

Substituting the values into the formula: - v = 2 * π * 384,000 / 2,360,320 - v ≈ 1,022.6 m/s

Centripetal Acceleration

Now, we can calculate the centripetal acceleration using the velocity and radius:

Centripetal acceleration (a) = (1,022.6)^2 / 384,000

Calculating: - a ≈ 2.73 * 10^-3 m/s^2

So, the centripetal acceleration of the Moon is approximately 2.73 * 10^-3 m/s^2.