Question

При работе компрессора внутренняя энергия алюминиевого поршнем массой 2 килограмма увеличилась на столько на сколько увеличилась внутренняя энергия воды массой 1 килограмм при нагревании от 0 градусов до 100 на сколько градусов повысилась при этом температура алюминиевого поршня?....пли . и при этом Напишите данно ирешение

Answer 1

Дано: m1=2 кг
m2=1kg
t1=0'C
t2=100'C
c1=920Дж/кг*градус цельсия
с2=4200Дж/кг*градус цельсия
Найти: t3
Решение:
Q=m2*c2*(t2-t1)
1кг*4200Дж/кг*градус цельсия*100'C=420000Дж
t3=Q/c1/m1
420000Дж/920Дж/кг*градус цельсия/2кг=228'C
Пояснения:
/ - Делить
* - умножить
'C - градус цельсия

Answer 2

Calculating the Temperature Increase of the Aluminum Piston

To calculate the temperature increase of the aluminum piston when its internal energy increases by the same amount as the internal energy increase of the water, we can use the specific heat capacity formula:

Q = mcΔT

Where: - Q is the heat added - m is the mass - c is the specific heat capacity - ΔT is the change in temperature

Specific Heat Capacities

The specific heat capacity of aluminum is approximately 0.902 J/g°C, and the specific heat capacity of water is approximately 4.18 J/g°C.

Calculating the Temperature Increase

Given: - Mass of aluminum piston, m_aluminum = 2 kg - Mass of water, m_water = 1 kg - Initial temperature of water, T_initial = 0°C - Final temperature of water, T_final = 100°C

First, let's calculate the heat added to the water: Q_water = m_water * c_water * ΔT_water

Where: - Q_water is the heat added to the water - m_water is the mass of water - c_water is the specific heat capacity of water - ΔT_water is the change in temperature of water

Q_water = 1 kg * 4.18 J/g°C * (100°C - 0°C)

Q_water = 418 J/g * 1 kg * 100°C

Q_water = 41800 J

Now, we can calculate the temperature increase of the aluminum piston using the same amount of heat added: Q_aluminum = m_aluminum * c_aluminum * ΔT_aluminum

Where: - Q_aluminum is the heat added to the aluminum piston - m_aluminum is the mass of the aluminum piston - c_aluminum is the specific heat capacity of aluminum - ΔT_aluminum is the change in temperature of the aluminum piston

Q_aluminum = 2 kg * 0.902 J/g°C * ΔT_aluminum

Since the heat added to the aluminum piston is the same as the heat added to the water: Q_aluminum = Q_water

2 kg * 0.902 J/g°C * ΔT_aluminum = 41800 J

Solving for ΔT_aluminum: ΔT_aluminum = 41800 J / (2 kg * 0.902 J/g°C)

ΔT_aluminum ≈ 23203.77°C

Therefore, the temperature of the aluminum piston increases by approximately 23203.77°C when its internal energy increases by the same amount as the internal energy increase of the water.

Conclusion

The temperature of the aluminum piston increases significantly due to the same increase in internal energy as the water, demonstrating the different effects of specific heat capacities on temperature changes.