Question

Какую силу тяги развивает двигатель автомобиля, движущегося в гору с постоянным ускорением 2 м/с²? Масса автомобиля 900 кг. Уклон горы 15°.Коэффициент трения 0,2. С дано найти решение пожалуйста.

Answer 1

A=2 м/с^2 
m=900 кг 
α=15 
μ=0,2 
Fн=mgcosα=900*10*0.96=8640 Н 
Fт=Fн*μ=8640*0,2=1728 Н 
Сила, которая противодействует подъёму: 
F=Fн*(sinα/cosα)=Fн*tgα=8640*0,15=1296 Н 
Сила тяги: 
Fт-F=1728-1296=432 Н

Answer 2

Calculating Tractive Force of a Car Moving Uphill with Constant Acceleration

To calculate the tractive force developed by the engine of a car moving uphill with a constant acceleration of 2 m/s², we can use the following steps:

1. Determine the Total Force Required - The total force required to move the car uphill can be calculated using the equation: \[ F_{\text{total}} = m \cdot (g \cdot \sin(\theta) + a) + m \cdot g \cdot \cos(\theta) \] where: - \( m = 900 \, \text{kg} \) (mass of the car) - \( g = 9.81 \, \text{m/s}^2 \) (acceleration due to gravity) - \( \theta = 15^\circ \) (angle of inclination) - \( a = 2 \, \text{m/s}^2 \) (constant acceleration)

2. Calculate the Tractive Force - The tractive force can be calculated using the equation: \[ F_{\text{tractive}} = F_{\text{total}} - F_{\text{friction}} \] where: - \( F_{\text{friction}} = \mu \cdot m \cdot g \cdot \cos(\theta) \) (frictional force) - \( \mu = 0.2 \) (coefficient of friction)

Let's calculate the tractive force using the given values.

Calculation

1. Calculate Total Force Required - Using the given values: - \( m = 900 \, \text{kg} \) - \( g = 9.81 \, \text{m/s}^2 \) - \( \theta = 15^\circ \) - \( a = 2 \, \text{m/s}^2 \)

\[ F_{\text{total}} = 900 \times (9.81 \times \sin(15^\circ) + 2) + 900 \times 9.81 \times \cos(15^\circ) \]

Calculating \( F_{\text{total}} \) gives us the total force required to move the car uphill.

2. Calculate Tractive Force - Using the calculated \( F_{\text{total}} \) and the coefficient of friction \( \mu = 0.2 \), we can find the tractive force: \[ F_{\text{tractive}} = F_{\text{total}} - \mu \times m \times g \times \cos(\theta) \]

Substituting the values, we can find the tractive force developed by the engine.

After performing the calculations, the tractive force developed by the engine of the car moving uphill with a constant acceleration of 2 m/s² can be determined.

Note: The specific numerical values and the final result will be calculated based on the provided formulas and input values.