Question

Рассчитайте наибольшую глубину, на которую опустился батискаф, если давление воды на поверхность батискафа равно 10(8) Па?

Answer 1

P1 = 10⁸ Па - давление на поверхность батискафа
h1 = ? - глубина погружения батискафа
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Давление пропорционально глубине погружения.
Известно, что столб воды высотой h = 10 м создаёт
давление р = 100 кПа = 10⁵ Па
Составим пропорцию:
h ----------p
h1---------p1
h1 = p1·h : p
h1 = 10⁸ · 10 : 10⁵  = 10⁴ (м) = 10 000 м = 10км
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Ответ: 10 км

Answer 2

Calculating the Maximum Depth of a Bathyscaphe

To calculate the maximum depth to which a bathyscaphe can descend given a water pressure of 10^8 Pascals, we can use the formula for pressure at a certain depth in a fluid:

P = ρgh

Where: - P = pressure - ρ = density of the fluid - g = acceleration due to gravity - h = depth

We can rearrange the formula to solve for depth:

h = P / (ρg)

Given that the density of seawater is approximately 1025 kg/m^3 and the acceleration due to gravity is approximately 9.81 m/s^2, we can substitute these values into the formula to find the depth.

Calculation

Using the given pressure of 10^8 Pascals, the density of seawater (ρ) of 1025 kg/m^3, and the acceleration due to gravity (g) of 9.81 m/s^2:

h = 10^8 / (1025 * 9.81)

Calculating the value:

h ≈ 10,194.17 meters

Therefore, the maximum depth to which the bathyscaphe can descend given a water pressure of 10^8 Pascals is approximately 10,194.17 meters.