Question

Какое количество кислорода выделится при разложении 35. мл 95% нитратной кислоты ( ро=1.5) и 17г. её натриевой соли. в каком случае больше?

Answer 1

M(HNO3)=35*1.5*0.95=49.9г
n(HNO3)=49.9:63=0.8моль
4HNO3=4NO2+2H2O+O2
4--------------------------------1
0.8----------------------------x      x=0.8:4=0.2моль O2,больше
2NaNO3=2NaNO2+O2
2----------------------------1
M(NaNO3)=85
n(NaNO3)=17:85=0.2 моль 
2---------------1
0.2-------------х   х=0.1моль O2 меньше

Answer 2

Calculation of Oxygen Released from Decomposition of Nitric Acid and Sodium Nitrate

To calculate the amount of oxygen released from the decomposition of 35 mL of 95% nitric acid (ρ=1.5) and 17 g of its sodium salt, we need to consider the chemical reaction involved.

The decomposition of nitric acid (HNO3) can be represented by the following equation:

2 HNO3 -> 2 NO2 + O2 + H2O

From this equation, we can see that for every 2 moles of nitric acid decomposed, 1 mole of oxygen gas (O2) is released.

To determine the moles of nitric acid and sodium nitrate, we need to use their molar masses. The molar mass of nitric acid (HNO3) is approximately 63 g/mol, and the molar mass of sodium nitrate (NaNO3) is approximately 85 g/mol.

Let's calculate the moles of nitric acid and sodium nitrate:

Moles of nitric acid = (volume of nitric acid / 1000) * (concentration of nitric acid / molar mass of nitric acid) Moles of sodium nitrate = mass of sodium nitrate / molar mass of sodium nitrate

Now, let's substitute the given values into the equations:

Moles of nitric acid = (35 mL / 1000) * (0.95 / 63 g/mol) Moles of sodium nitrate = 17 g / 85 g/mol

After calculating the moles of nitric acid and sodium nitrate, we can determine the moles of oxygen released:

Moles of oxygen released = (moles of nitric acid / 2)

Now, let's calculate the moles of oxygen released:

Moles of oxygen released = (35 mL / 1000) * (0.95 / 63 g/mol) / 2

To convert the moles of oxygen released to grams, we can use the molar mass of oxygen, which is approximately 32 g/mol:

Grams of oxygen released = Moles of oxygen released * molar mass of oxygen

Now, let's calculate the grams of oxygen released:

Grams of oxygen released = [(35 mL / 1000) * (0.95 / 63 g/mol) / 2] * 32 g/mol

To determine which case results in a larger amount of oxygen released, we need to compare the grams of oxygen released from the decomposition of nitric acid and sodium nitrate.

Please note that due to the lack of specific information about the concentration of the sodium nitrate solution, we cannot provide an exact comparison. However, we can compare the theoretical maximum amount of oxygen released from the given amounts of nitric acid and sodium nitrate.

Comparison of Oxygen Released

To compare the amounts of oxygen released, we need to calculate the grams of oxygen released from the decomposition of sodium nitrate. However, without the specific concentration of the sodium nitrate solution, we cannot provide an accurate comparison.

In general, the decomposition of nitric acid releases more oxygen than the decomposition of sodium nitrate. This is because nitric acid contains more oxygen atoms per molecule compared to sodium nitrate.

However, to provide a more precise comparison, we would need the concentration of the sodium nitrate solution.