Question

2) электрон начальная скорость которого равна нулю начинает двигаться в однородном поле напряженностью 1,5 в/м. На каком расстоянии его скорость возрастает до 2000 км/с? масса электорона m=9,1*10 в минус 31 степени кг, а модуль его заряда e=1.6*10 в минус 19 степени Кл.

Answer 1

По закону сохранения энергии m*V^2/2=E*e*S
S=m*V^2/2*E*e=9,1*10^-31*4*10^12/1,5*1,6*10^-19=15,17 м

Answer 2

Calculation of the Distance for the Electron's Speed to Increase to 2000 km/s

To calculate the distance at which the electron's speed increases to 2000 km/s in a uniform electric field with an intensity of 1.5 V/m, we can use the equation of motion for a charged particle in an electric field.

The equation of motion for a charged particle in an electric field is given by:

F = qE

Where: - F is the force experienced by the charged particle, - q is the charge of the particle, and - E is the electric field intensity.

In this case, the charged particle is an electron with a charge of e = 1.6 x 10^-19 C and a mass of m = 9.1 x 10^-31 kg.

The force experienced by the electron can be calculated using the equation:

F = ma

Where: - m is the mass of the electron, and - a is the acceleration of the electron.

Since the initial velocity of the electron is zero, the acceleration can be calculated using the equation:

a = F/m

Substituting the values, we get:

a = (qE)/m

Now, we can calculate the acceleration of the electron in the electric field:

a = (1.6 x 10^-19 C) x (1.5 V/m) / (9.1 x 10^-31 kg)

Let's calculate the value of 'a':

a = (1.6 x 10^-19 C) x (1.5 V/m) / (9.1 x 10^-31 kg)