Question

Период колебаний пружинного маятника 0,25 с. Чему равна жесткость пружины, если масса груза 200 г? Помогите!!!!!!!!

Answer 1

Т=2п* корень из ( m/k); k=4 п^2*m/Т^2 =4*3,14*3,14*0,2/(0,25*0,25)=126,2

Answer 2

Period of Oscillation of a Spring Pendulum

The period of oscillation of a spring pendulum can be calculated using the formula:

T = 2π√(m/k)

Where: - T = period of oscillation - m = mass of the object attached to the spring - k = spring constant (also known as stiffness or rigidity of the spring)

Given: - Period of oscillation (T) = 0.25 s - Mass of the object (m) = 200 g

Calculating the Spring Constant

To find the spring constant (k), we can rearrange the formula as follows:

k = (4π²m) / T²

Substitute the given values: - m = 200 g = 0.2 kg (converting to kilograms) - T = 0.25 s

Now, let's calculate the spring constant using the given values.

k = (4π² * 0.2) / (0.25)²

k ≈ 100 N/m

The spring constant is approximately 100 N/m.

[[2 #]] provides a formula for the spring constant and mass, which aligns with the calculation performed.