Question

Один маятник имеет период 5 с,другой 3 с.Каков период колебаний математического маятника ,длина которого равна разности длин маятников?решите пожалуйста по подробнее дано и решение и если что то переводить тоже ..)

Answer 1

дано T1=5C T2=3C 

 

 

T=

l=T^{2}*g
l1=90
l2=250
T3=корень из 250+90=340/10
T3=1.8

Answer 2

Calculation of the Period of a Mathematical Pendulum

To find the period of a mathematical pendulum, we need to consider the lengths of the two pendulums given and calculate the difference in their lengths.

Let's assume that the length of the first pendulum is L1 and the length of the second pendulum is L2. The period of the first pendulum is T1 = 5 seconds, and the period of the second pendulum is T2 = 3 seconds.

The period of a mathematical pendulum is given by the formula:

T = 2π√(L/g)

Where: - T is the period of the pendulum - L is the length of the pendulum - g is the acceleration due to gravity (approximately 9.8 m/s^2)

To find the period of the mathematical pendulum with a length equal to the difference in lengths of the two given pendulums, we can subtract the lengths of the pendulums:

L = |L1 - L2|

Let's calculate the period of the mathematical pendulum:

L = |L1 - L2| = |L1 - L2| seconds

T = 2π√(L/g) = 2π√(|L1 - L2|/g) seconds

Now, let's substitute the given values into the formula and calculate the period of the mathematical pendulum.

T = 2π√(|L1 - L2|/g) seconds

Please provide the values of L1 and L2 so that we can calculate the period of the mathematical pendulum.