Question

На проводнике длиной 50 см с током 2А однородное магнитное поле с магнитной индукцией 0,1 Тл действует с силой 0,05 Н. Вычислите угол между направлением тока и вектором магнитной индукции. Заранее спасибо!

Answer 1

F=IBlsinL

sinL=F/IBl

sinL=0,05/0,5*2* 0,1=1/2

L=30градусов

Answer 2

Calculation of the Angle between the Current and Magnetic Field

To calculate the angle between the direction of the current and the magnetic field, we can use the formula:

F = BILsinθ

Where: - F is the force experienced by the conductor, - B is the magnetic field strength (also known as magnetic induction), - I is the current flowing through the conductor, - L is the length of the conductor, and - θ is the angle between the direction of the current and the magnetic field.

In this case, we are given the following values: - Length of the conductor (L) = 50 cm = 0.5 m - Current (I) = 2 A - Magnetic induction (B) = 0.1 T - Force (F) = 0.05 N

We can rearrange the formula to solve for θ:

θ = arcsin(F / (BIL))

Substituting the given values:

θ = arcsin(0.05 / (0.1 * 2 * 0.5))

Now, let's calculate the value of θ using the given formula:

θ = arcsin(0.05 / (0.1 * 2 * 0.5)) = arcsin(0.05 / 0.1) = arcsin(0.5) ≈ 30.0°

Therefore, the angle between the direction of the current and the magnetic field is approximately 30.0°.