Question

Площадь поперечного сечения парохода на уровне воды равна 3000м2. Глубина осадки парохода по окончании погрузки увеличилась на 2м. Определите массу груза, принятого пароходом.

Answer 1

Дано:  S = 3000 м2;  h= 2 м р воды = 1000 кг/м3.
m гр - ?
Архимедова сила возросла на вес дополнительно вытесненной воды после загрузки судна. Таким образом вес дополнительно вытесненной воды будет равен весу груза, принятого на борт судна. Вес воды Fв = V*p = S*h*p*g.
 Вес груза Fг = m*g. 
Fв = Fг.   Т.е. S*h*p*g= m*g.  Или   S*h*p= m = 3000*2*1000 = 6000000 кг = 6000 тонн.

Answer 2

Calculation of the Mass of Cargo Accepted by the Steamship

To calculate the mass of the cargo accepted by the steamship, we need to consider the change in draft (depth of immersion) of the ship after loading the cargo. The given information states that the area of the cross-section of the ship at the water level is 3000 m², and the draft of the ship increased by 2 meters after loading.

The formula to calculate the mass of the cargo is:

Mass of Cargo = Density of Water x Volume of Water Displaced

To find the volume of water displaced, we can use the formula:

Volume of Water Displaced = Area of Cross-Section x Change in Draft

Let's calculate the mass of the cargo:

1. Calculate the volume of water displaced: - Area of Cross-Section = 3000 m² - Change in Draft = 2 m

Volume of Water Displaced = 3000 m² x 2 m = 6000 m³.

2. The density of water is approximately 1000 kg/m³.

Density of Water = 1000 kg/m³.

3. Calculate the mass of the cargo: - Mass of Cargo = Density of Water x Volume of Water Displaced - Mass of Cargo = 1000 kg/m³ x 6000 m³

Mass of Cargo = 6,000,000 kg.

Therefore, the mass of the cargo accepted by the steamship is 6,000,000 kg.