Question

При погружении в мензурку с водой железной гайки вода поднялась с отметки 60 куб.см.до отметки 70 куб.см. Найти архимедову силу, действующую на гайку. ПЛЛИИИЗЗЗЗЗЗ

Answer 1

F(архимеда)=P(плотность жидкости)*g(ускорение свободного падения)*V(объем погруженного тела)=
V=70-60=10 куб.см воды=0.01литра
F=1000*9,8*0,01=98 ньютонов

Answer 2

Archimedes' Principle and Buoyancy

When an object is submerged in a fluid, it experiences an upward force called buoyancy. This force is equal to the weight of the fluid displaced by the object. Archimedes' principle states that the buoyant force acting on an object is equal to the weight of the fluid displaced by the object.

Calculation of Buoyant Force

To calculate the buoyant force acting on the iron nut, we need to determine the weight of the water displaced by the nut. The difference in volume between the initial and final water levels in the measuring cylinder represents the volume of water displaced by the nut.

Given: - Initial water level: 60 cubic centimeters (cm^3) - Final water level: 70 cubic centimeters (cm^3)

The volume of water displaced by the nut can be calculated as follows: Volume of water displaced = Final water level - Initial water level Volume of water displaced = 70 cm^3 - 60 cm^3 Volume of water displaced = 10 cm^3

Density of Water

To calculate the weight of the water displaced, we need to know the density of water. The density of water is approximately 1 gram per cubic centimeter (g/cm^3) or 1000 kilograms per cubic meter (kg/m^3).

Calculation of Weight of Water Displaced

The weight of the water displaced can be calculated using the formula: Weight = Density * Volume * Acceleration due to gravity

Given: - Density of water = 1 g/cm^3 = 1000 kg/m^3 - Volume of water displaced = 10 cm^3 - Acceleration due to gravity = 9.8 m/s^2

Weight of water displaced = Density * Volume * Acceleration due to gravity Weight of water displaced = 1000 kg/m^3 * 10 cm^3 * (1 m^3 / 1000000 cm^3) * 9.8 m/s^2 Weight of water displaced = 0.098 Newtons (N)

Calculation of Buoyant Force

According to Archimedes' principle, the buoyant force acting on the iron nut is equal to the weight of the water displaced. Therefore, the buoyant force acting on the nut is 0.098 Newtons (N).

The Archimedes' force acting on the iron nut is 0.098 Newtons (N).

Please note that the calculations provided are based on the assumption that the density of the iron nut is greater than the density of water, causing it to sink.