Question

С каким ускорением скользит тело вниз по наклонной плоскости с углом 30 градусов при коэффициенте трения 0,2?

Answer 1

M*a=m*g*sina-k*m*g*cosa
a=g*(sina-k*cosa)=10*(0,5-0,2*0,87)=3,26  м/с2

Answer 2

Calculating Acceleration of an Object Sliding Down an Incline

To calculate the acceleration of an object sliding down a slope with a 30-degree angle and a coefficient of friction of 0.2, we can use the following steps:

1. Determine the Normal Force (N): - The normal force (N) can be calculated using the formula N = mg * cos(θ), where m is the mass of the object, g is the acceleration due to gravity, and θ is the angle of the incline. - Using the given information, we can calculate the normal force.

Calculation: N = mg * cos(30°) = 5 * 10 * cos(30°) = 5 * 10 * 0.866 = 43.3 N 2. Calculate the Frictional Force (F): - The frictional force (F) can be calculated using the formula F = μN, where μ is the coefficient of friction and N is the normal force.

Calculation: F = 0.2 * 43.3 = 8.66 N 3. Determine the Net Force (F_net): - The net force (F_net) can be calculated by subtracting the frictional force from the component of the gravitational force parallel to the incline.

Calculation: F_net = mg * sin(θ) - F = 5 * 10 * sin(30°) - 8.66 = 25 - 8.66 = 16.34 N 4. Calculate the Acceleration (a): - The acceleration (a) can be calculated using the formula a = F_net / m, where m is the mass of the object.

Calculation: a = F_net / m = 16.34 / 5 = 3.268 m/s^2

Conclusion

The acceleration of the object sliding down the incline with a 30-degree angle and a coefficient of friction of 0.2 is approximately 3.268 m/s^2.