Question

1. Построй графики для каждого тела и узнай, какой вид движения? t, с 0 1 2 3 4 5 x1 м 6 4 2 0 -2 -4 х2, м -3 -3 -3 -3 -3 -3 х4, м 0 2 4 2 0 -2 это таблица там все цифры друг под другом

Answer 1

Вот,где х4 там либо прямолин.,равномер.,либо равноускоренное,если проходили,то скорее всего равноуск.)

Answer 2

Graphs and Motion Analysis

To analyze the motion of the given bodies, let's first plot the provided data points on a graph and then determine the type of motion for each body.

The given table is as follows:

| t | x1 | x2 | x4 | | --- | --- | --- | --- | | 0 | 6 | -3 | 0 | | 1 | 4 | -3 | 2 | | 2 | 2 | -3 | 4 | | 3 | 0 | -3 | 2 | | 4 | -2 | -3 | 0 | | 5 | -4 | -3 | -2 |

Let's plot the graphs for each body using the given data points.

Graph for Body x1:

```plaintext t (time) | x1 (position) ------------------------- 0 | 6 1 | 4 2 | 2 3 | 0 4 | -2 5 | -4 ``` Type of Motion for x1: The graph of x1 shows a linear decrease in position over time, indicating uniformly accelerated motion.

Graph for Body x2:

```plaintext t (time) | x2 (position) ------------------------- 0 | -3 1 | -3 2 | -3 3 | -3 4 | -3 5 | -3 ``` Type of Motion for x2: The graph of x2 shows a constant position over time, indicating stationary motion.

Graph for Body x4:

```plaintext t (time) | x4 (position) ------------------------- 0 | 0 1 | 2 2 | 4 3 | 2 4 | 0 5 | -2 ``` Type of Motion for x4: The graph of x4 shows a symmetrical increase and then decrease in position over time, indicating oscillatory motion.

These analyses are based on the provided data points and the corresponding graphs.

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