Question

найдите энергию фотона видимого света с длиной волны 500 нм

Answer 1

E = (6,63*10^(-34)*3*10^(8))/(5*10^(-7)) = (примерно) 4*10^(-19) Дж 

Answer 2

Решение:

E=h*∨

v-частота

v=с/ λ

c-cкорость света

λ-длина волны

E=(h*c)/λ

E=(6.63*10^-34*3*10^8)/(5*10^-7)=3.978*10^-19 Дж

Answer 3

Calculating the Energy of a Photon in Visible Light

To calculate the energy of a photon in visible light with a wavelength of 500 nm, we can use the formula:

E = hc/λ

Where: - E = energy of the photon - h = Planck's constant (6.626 x 10^-34 J·s) - c = speed of light in a vacuum (3.00 x 10^8 m/s) - λ = wavelength of the light in meters

Calculation

Using the given wavelength of 500 nm (which is 500 x 10^-9 m), we can calculate the energy of the photon:

E = (6.626 x 10^-34 J·s * 3.00 x 10^8 m/s) / (500 x 10^-9 m)

E ≈ 3.97 x 10^-19 J

Therefore, the energy of a photon in visible light with a wavelength of 500 nm is approximately 3.97 x 10^-19 joules.