Question

Пожалуйста помогите.Очень надо. Дифракционую решетку которая имеет 50 штрихов на 1 мм, освещают белым светом длины волн (от 400 до 780 нм).Какая ширина спектра первого порядка на экране на растоянии 4м. от решетки?

Answer 1

Это очень сложно. Мне не решить(

Answer 2

Calculating the Spectral Width of the First Order

To calculate the spectral width of the first order on the screen at a distance of 4m from the grating, we can use the formula:

Δλ = λ / mN

Where: - Δλ is the spectral width - λ is the wavelength of light - m is the order of the spectrum - N is the number of lines per unit length

Given: - λ (wavelength of light) ranges from 400nm to 780nm - N (number of lines per unit length) is 50 lines/mm - m (order of the spectrum) is 1 - Distance from the grating to the screen is 4m

Calculating the Spectral Width for λ = 400nm

Using the formula, we can calculate the spectral width for λ = 400nm:

Δλ = (400 * 10^-9) / (1 * 50 * 10^3)

Calculating Δλ: ``` Δλ = (400 * 10^-9) / (1 * 50 * 10^3) = 8 * 10^-12 meters ```

Calculating the Spectral Width for λ = 780nm

Now, let's calculate the spectral width for λ = 780nm:

Δλ = (780 * 10^-9) / (1 * 50 * 10^3)

Calculating Δλ: ``` Δλ = (780 * 10^-9) / (1 * 50 * 10^3) = 15.6 * 10^-12 meters ```

Conclusion

The spectral width of the first order on the screen at a distance of 4m from the grating ranges from approximately 8 * 10^-12 meters to 15.6 * 10^-12 meters, depending on the wavelength of the incident light.

I hope this helps! If you have any further questions, feel free to ask.