Question

Из баллона со сжатым водородом емкостью 10л вследствие неисправности вентиля утекает газ. При температуре 7°С манометр показывал давление 5*10^6 Па. Через некоторое время при температуре 17 °С манометр показывал такое же давление. Какая масса газа утекла?

Answer 1

8литров Надеюсь успел

Answer 2

Calculation of the Mass of Gas Leaked

To calculate the mass of gas leaked from the cylinder, we need to use the ideal gas law equation, which states:

PV = nRT

Where: - P is the pressure of the gas (in Pascals) - V is the volume of the gas (in liters) - n is the number of moles of gas - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature of the gas (in Kelvin)

We are given the following information: - The volume of the cylinder is 10 liters. - The initial temperature is 7°C, which is equivalent to 280 Kelvin. - The pressure is 5 * 10^6 Pascals at both temperatures.

To calculate the mass of the gas leaked, we need to find the difference in the number of moles of gas between the initial and final states.

Using the ideal gas law equation, we can rearrange it to solve for the number of moles:

n = PV / RT

Let's calculate the number of moles of gas in the initial state:

n_initial = (P_initial * V) / (R * T_initial)

Substituting the given values: - P_initial = 5 * 10^6 Pascals - V = 10 liters - R = 8.314 J/(mol·K) - T_initial = 280 Kelvin

We can now calculate n_initial.

Next, let's calculate the number of moles of gas in the final state:

n_final = (P_final * V) / (R * T_final)

Substituting the given values: - P_final = 5 * 10^6 Pascals - V = 10 liters - R = 8.314 J/(mol·K) - T_final = 290 Kelvin

We can now calculate n_final.

Finally, to find the mass of the gas leaked, we subtract n_final from n_initial and multiply by the molar mass of hydrogen, which is approximately 2 grams/mol.

Let's perform the calculations: