Question

Дене 80м биіктіктен еркін құлағанда түсу уақытының соңғы секундындағы орын ауыстыруы шыгару жолымен

Answer 1

T=2π$\sqrt{L/g}$=2*3,14*2,82=17,7 сек

Answer 2

Determining the Position of the Ear at the End of 80 Meters of Free Fall

When an object falls freely under the influence of gravity, its position can be determined using the equations of motion. In this case, we want to determine the position of the ear at the end of 80 meters of free fall.

To solve this problem, we can use the equation for the position of an object in free fall:

y = y0 + v0t + (1/2)gt^2

Where: - y is the final position of the object - y0 is the initial position of the object (in this case, the position of the ear at the start of the free fall) - v0 is the initial velocity of the object (in this case, the velocity of the ear at the start of the free fall) - t is the time elapsed during the free fall - g is the acceleration due to gravity (approximately 9.8 m/s^2)

In this case, we are given that the ear falls freely for 80 meters. Therefore, y0 = 0 (assuming the initial position is at ground level) and y = -80 (since the ear falls downward).

We need to find the time it takes for the ear to fall 80 meters. Rearranging the equation, we have:

80 = 0 + v0t + (1/2)(9.8)t^2

Simplifying the equation, we get:

4.9t^2 + v0t - 80 = 0

This is a quadratic equation in terms of t. We can solve it using the quadratic formula:

t = (-v0 ± √(v0^2 - 4(4.9)(-80))) / (2(4.9))

Since we are only interested in the positive value of t (the time it takes for the ear to fall), we can ignore the negative solution.

Now, let's find the value of v0. The initial velocity of the ear can be calculated using the equation:

v0 = gt

Substituting the value of t into the equation, we get:

v0 = (9.8)t

Now we can substitute the value of v0 into the quadratic formula to find the value of t.

Please note that the above calculations assume that the only force acting on the ear is gravity and neglects air resistance. Additionally, the calculations assume that the ear is dropped from rest and not thrown or given an initial velocity.

I hope this explanation helps! Let me know if you have any further questions.