Question

Брусок массой 3 кг скользит по наклонной плоскости с углом наклона 30 градусов. Коефициэнт трения бруска о плоскость равен 0.3. Чему равна сила трения плоскости о брусок?

Answer 1

F тр = mgM
F тр = 3 * 0,3 * 9,8 = 8,82 Н
______
М - это мю

Answer 2

Calculation of the Frictional Force

To calculate the frictional force between the inclined plane and the block, we need to consider the weight of the block and the angle of inclination.

Given: - Mass of the block (m): 3 kg - Angle of inclination (θ): 30 degrees - Coefficient of friction between the block and the plane (μ): 0.3

To find the frictional force, we can use the formula:

Frictional Force (F) = Coefficient of Friction (μ) × Normal Force (N)

The normal force (N) can be calculated using the formula:

Normal Force (N) = Weight of the Block (mg)

where: - Weight of the Block (mg) = mass of the block (m) × acceleration due to gravity (g)

The acceleration due to gravity is approximately 9.8 m/s^2.

Let's calculate the frictional force step by step.

1. Calculate the weight of the block: - Weight of the Block (mg) = mass of the block (m) × acceleration due to gravity (g) - Weight of the Block (mg) = 3 kg × 9.8 m/s^2 = 29.4 N 2. Calculate the normal force: - Normal Force (N) = Weight of the Block (mg) - Normal Force (N) = 29.4 N

3. Calculate the frictional force: - Frictional Force (F) = Coefficient of Friction (μ) × Normal Force (N) - Frictional Force (F) = 0.3 × 29.4 N = 8.82 N

Therefore, the frictional force between the inclined plane and the block is 8.82 N.

Please note that the calculations assume ideal conditions and do not take into account other factors such as air resistance or the possibility of the block accelerating down the incline.