Question

Найти коэффициент жесткости пружины,если известно, что работа сжатия пружины на х=10см равна 200Дж

Answer 1

Дано:
А = 200 Дж
x = 10 см = 0,10 м
 __________
   k - ?

Работа силы упругшости:
A = k*x² / 2
Отсюда:
k = 2*A / x² = 2*200 / 0,01 = 40 000 Н/м = 40 кН/м

Answer 2

Finding the Spring Constant (Коэффициент жесткости пружины)

To find the spring constant (коэффициент жесткости пружины), we can use the formula for the potential energy stored in a spring:

U = (1/2)kx^2

Where: - U is the potential energy stored in the spring - k is the spring constant - x is the displacement of the spring from its equilibrium position

In this case, we know that the work done on the spring during compression (сжатия) is 200 J (Дж) and the displacement (x) is 10 cm (0.1 m). We can equate the work done to the potential energy stored in the spring:

200 J = (1/2)k(0.1 m)^2

Simplifying the equation, we have:

200 J = (1/2)k(0.01 m^2)

To find the spring constant (k), we can rearrange the equation:

k = (2 * 200 J) / (0.01 m^2)

Evaluating the expression, we find:

k = 40000 N/m

Therefore, the spring constant (коэффициент жесткости пружины) is 40000 N/m.