Question

Поезд, двигаясь со станции с ускорением 0,4 м/с^2, прошёл путь 0,5 км. Какой скорости при этом достиг поезд?

Answer 1

A=0,4 м/с^2,  s= 0,5 км = 500 м, v0=0, v-? v^2-v0^2=2as; v=√(2as)=√(2*0,4*500)=20 м/с.

Answer 2

Calculating the Train's Final Velocity

To calculate the final velocity of the train, we can use the following kinematic equation:

v^2 = u^2 + 2as

Where: - v = final velocity - u = initial velocity (assumed to be 0 m/s as the train starts from rest) - a = acceleration (0.4 m/s^2) - s = distance traveled (0.5 km = 500 m)

Plugging in the values, we get:

v^2 = 0 + 2 * 0.4 * 500

Let's calculate the final velocity.