Question

Какую мощность развивает трактор при равномерном движении со скоростью 2 м/c, если у трактора сила тяги 12 кН?

Answer 1

Дано: V=2M/C, F=12kH. N=?
Си: F=12000H.
Формула: N=A/t, N=FS/t, S и t сокращаются - получаем рабочую формулу - N=FV.
Решение: N=12000H*2M/C=24000Вт=24кВт.

Answer 2

Calculating Tractor Power

To calculate the power developed by a tractor moving at a constant speed of 2 m/s with a pulling force of 12 kN, we can use the formula:

Power (P) = Force (F) × Velocity (V)

Given: - Force (F) = 12 kN - Velocity (V) = 2 m/s

Using the above formula, we can calculate the power developed by the tractor.

Power (P) = 12 kN × 2 m/s

Calculation

Power (P) = 24 kW

Therefore, the tractor develops a power of 24 kW when moving at a constant speed of 2 m/s with a pulling force of 12 kN.

This calculation is based on the provided formula and values.