Question

За какое время автомобиль,двигаясь из состояния покоя с ускорением 1.2 м/с^2,пройдет 60 м?

Answer 1

a=1.2     s=60   t=?

t=√(2*s/a)=(2*60/1.2)=10 c

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Answer 2

$t= \sqrt{S*2/a}$
t=60*2/1.2=$\sqrt{100}$=10c

Answer 3

Calculating Time Taken to Travel with Constant Acceleration

To calculate the time it takes for a car to travel a distance of 60 meters with a constant acceleration of 1.2 m/s^2, we can use the following kinematic equation:

\[s = v0t + (1/2)at^2\]

Where: - s = distance traveled (60 m) - v0 = initial velocity (0 m/s, as the car starts from rest) - a = acceleration (1.2 m/s^2) - t = time taken

We can rearrange the equation to solve for t:

\[t = sqrt((2s) / a)\]

Substituting the given values:

\[t = sqrt((2 * 60) / 1.2) = sqrt(120 / 1.2) = sqrt(100) = 10 s\]

So, the car will take 10 seconds to travel a distance of 60 meters with an acceleration of 1.2 m/s^2.

Conclusion

The time taken for the car to travel 60 meters with an acceleration of 1.2 m/s^2 is 10 seconds.