Question

Какое перемещение совершит самолет за 10с. прямолинейного разбега при начальной скорости 10м/с и ускорения 1,5м/с^2

Answer 1

S=V0*t+(a*t^2)/2
S=10*10+0,75*100=100+75=175

Answer 2

V=v0+a*t=10+1.5*10=25 м/с

S=v0*t + a*t2/2=10*10+1.5*100/2=100+75=175 м

Ответ 175

Answer 3

Calculation of the Plane's Displacement

To calculate the displacement of the plane during a 10-second straight run with an initial velocity of 10 m/s and an acceleration of 1.5 m/s^2, we can use the equations of motion.

The equation for displacement is given by:

S = ut + (1/2)at^2

Where: - S is the displacement - u is the initial velocity - t is the time - a is the acceleration

Substituting the given values into the equation, we have:

S = (10 m/s)(10 s) + (1/2)(1.5 m/s^2)(10 s)^2

Simplifying the equation, we get:

S = 100 m + 0.5(1.5 m/s^2)(100 s^2)

Calculating further:

S = 100 m + 0.5(1.5 m/s^2)(100 s^2) = 100 m + 0.5(150 m) = 100 m + 75 m = 175 m

Therefore, the plane will have a displacement of 175 meters during the 10-second straight run.

Please let me know if there's anything else I can help you with!