Question

Тело объёмом 2 м(кубических)погружено в воду.Надо найти Архимедову силу действующую на тело

Answer 1

Архимедова Сила:
F=pgV
F=1000*10*0,2=2КилоНьютона

Answer 2

Calculation of Archimedes' Force

To calculate the Archimedes' force acting on an object submerged in water, we need to use the formula:

F = ρ * g * V

Where: - F is the Archimedes' force - ρ is the density of the fluid (in this case, water) - g is the acceleration due to gravity - V is the volume of the object submerged in the fluid

In this case, the volume of the object submerged in water is given as 2 m³. To find the Archimedes' force, we need to know the density of water and the acceleration due to gravity.

According to the search results, the acceleration due to gravity (g) is approximately 9.8 m/s².

The density of water (ρ) is not explicitly mentioned in the search results. However, the density of water is commonly known to be approximately 1000 kg/m³. We will use this value for our calculation.

Substituting the values into the formula, we get:

F = (1000 kg/m³) * (9.8 m/s²) * (2 m³)

Calculating the result:

F ≈ 19,600 N

Therefore, the Archimedes' force acting on the object submerged in water with a volume of 2 m³ is approximately 19,600 Newtons.