Question

ПОМОГИТЕ ПОЖАЛУЙСТА, ОЧЕНЬ НАДОсмешали 78 кг воды при температуре 20 градусов и 42 кг воды при температуре 60 градусов. Определите температуру смеси

Answer 1

1 Найдем тепло отданное горячей водой Q1= c*m1*(60-t)
2 Вычислим тепло принятое холодной водой Q2=c*m2(t-20)
Так как потерь энергии нет то
m2(t-20)=m1(60-t)
78(t-20)=42(60-t)
раскрой скобки и реши уравнение

Answer 2

Calculating the Final Temperature of the Water Mixture

To determine the final temperature of the water mixture, we can use the principle of conservation of energy, which states that the total heat lost by the hot water will be equal to the total heat gained by the cold water.

Let's calculate the final temperature using the formula for heat transfer:

m1c1ΔT1 = m2c2ΔT2

Where: - m1 = mass of the first substance (in this case, the first quantity of water) - c1 = specific heat capacity of the first substance (for water, this is approximately 4.18 J/g°C) - ΔT1 = change in temperature of the first substance - m2 = mass of the second substance (in this case, the second quantity of water) - c2 = specific heat capacity of the second substance - ΔT2 = change in temperature of the second substance

We can calculate the final temperature of the water mixture using this formula.

Calculation Steps

1. Calculate the heat lost by the hot water: - m1 = 42 kg - c1 = 4.18 J/g°C (specific heat capacity of water) - ΔT1 = 60°C - TF (where TF is the final temperature of the mixture)

2. Calculate the heat gained by the cold water: - m2 = 78 kg - c2 = 4.18 J/g°C (specific heat capacity of water) - ΔT2 = TF - 20°C (where TF is the final temperature of the mixture)

3. Set the two equations equal to each other and solve for TF.

Final Temperature Calculation

Using the formula m1c1ΔT1 = m2c2ΔT2, we can calculate the final temperature of the water mixture. Let's proceed with the calculation.