Question

Электровоз движется с постоянной скоростью и ведёт состав массой 1800 т. Сила тока, потребляемая электровозом из сети напряжением 3000 В, равна 750 А. Коэффициент трения равен 0,005. КПД двигателя электровоза 80%. Определите скорость движения электровоза.

Answer 1

КПД = Рп/Рз

Рп = FтягиV

по 2 з.Н. Fтяги = Fтрения = µN = µmg

Pз = UI

Тогда:

КПД = µmgV/UI

0.8 = 0.005 * 1800000 * 10 * V / 750 * 3000

Посчитав, получаем, что V = 20 м/с

Answer 2

Calculation of the Speed of the Electric Locomotive

To determine the speed of the electric locomotive, we can use the formula:

V = P / (F * μ)

Where: - V is the velocity of the locomotive - P is the power consumed by the locomotive from the power supply - F is the force exerted by the locomotive - μ is the coefficient of friction

Given the following information: - Mass of the train (m) = 1800 tons = 1800000 kg - Current (I) = 750 A - Voltage (V) = 3000 V - Coefficient of friction (μ) = 0.005 - Efficiency of the locomotive's motor = 80%

First, let's calculate the power consumed by the locomotive:

P = V * I

Substituting the given values: P = 3000 V * 750 A = 2250000 W

Next, let's calculate the force exerted by the locomotive:

F = P / V

Substituting the values: F = 2250000 W / 3000 V = 750 N

Now, we can calculate the velocity of the locomotive:

V = P / (F * μ)

Substituting the values: V = 2250000 W / (750 N * 0.005) = 600 m/s

Therefore, the speed of the electric locomotive is 600 m/s.

Please note that this calculation assumes ideal conditions and does not take into account factors such as air resistance or other external forces that may affect the actual speed of the locomotive.