Question

3 литра воды взятой при температуре 20С смешали с водой при температуре 100С.температура смеси равна 40С.чему равна масса горячей воды?

Answer 1

Дано   m1=3 кг     t1=20C         t2=100C   t=40C    m2-?

Q2=c*m2*(t2-t)

Q1=c*m1*(t-t1)

Q1=Q2

m2=m1*(t-t1)/(t2-t)=3*10/60=0,5 кг- ответ

Answer 2

Calculating the Mass of Hot Water

To calculate the mass of the hot water, we can use the principle of mixtures. When two substances at different temperatures are mixed, the resulting temperature is a weighted average of the original temperatures, based on the masses of the substances.

Given: - Initial temperature of the first water sample (3 liters) = 20°C - Initial temperature of the second water sample = 100°C - Final temperature of the mixture = 40°C

Using the principle of mixtures, we can calculate the mass of the hot water.

Let's denote: - m1 = mass of the first water sample (3 liters) at 20°C - m2 = mass of the second water sample at 100°C - T1 = initial temperature of the first water sample (20°C) - T2 = initial temperature of the second water sample (100°C) - Tf = final temperature of the mixture (40°C)

The formula to calculate the mass of the hot water is: m2 = (m1 * (T1 - Tf)) / (Tf - T2)

Substitute the given values: m2 = (3 * (20 - 40)) / (40 - 100)

Calculating: m2 = (3 * (-20)) / (-60) m2 = 60 / 60 m2 = 1

Answer

The mass of the hot water is 1 kilogram.