Question

Математический маятник длиной 1 м установлен в лифте. Найдите период колебаний маятника, если лифт движется вертикально вниз с ускорением 3 м/с^2. напишите полное решение пожалуйста)

Answer 1

Извините но я не знаю

Answer 2

Calculation of the Period of a Pendulum in an Elevator

To find the period of oscillation of a pendulum in an elevator moving vertically downward with an acceleration of 3 m/s^2, we can use the formula for the period of a simple pendulum:

T = 2π√(L/g)

Where: - T is the period of the pendulum, - L is the length of the pendulum, and - g is the acceleration due to gravity.

In this case, the length of the pendulum is given as 1 m, and the acceleration due to gravity is approximately 9.8 m/s^2.

Substituting these values into the formula, we have:

T = 2π√(1/9.8)

Calculating this expression, we find:

T ≈ 2π√(0.102)

T ≈ 2π(0.319)

T ≈ 2.006 seconds

Therefore, the period of oscillation of the pendulum in the elevator is approximately 2.006 seconds.

Please note that the above calculation assumes that the length of the pendulum remains constant throughout the motion and that the acceleration due to gravity is constant.