Question

Помогите решить термодинамику, внутренняя энергиядано v=2 * м³, P=2 *10^5па, молярная масса 28 кг/ Н*моль, темп 27 цельсиев азотанайти массу

Answer 1

PV=m/MRT
pVM=mRT
m=pVM/RT
m=2*10⁵*2*10⁻³*28*10⁻³/(8,31*300)=4,49*10⁻³кг=4,49г

Answer 2

Solving for Mass using Thermodynamic Parameters

To find the mass of the given nitrogen gas, we can use the ideal gas law equation, which relates the pressure, volume, temperature, and the number of moles of a gas. The ideal gas law equation is given by:

PV = nRT

Where: - P = pressure (in Pascals) - V = volume (in cubic meters) - n = number of moles - R = ideal gas constant (8.314 J/(mol·K)) - T = temperature (in Kelvin)

We are given: - V = 2 m³ - P = 2 * 10^5 Pa - Molar mass = 28 kg/mol - Temperature = 27°C

First, let's convert the temperature from Celsius to Kelvin: T(K) = T(°C) + 273.15

T(K) = 27 + 273.15 = 300.15 K

Now, we can calculate the number of moles using the ideal gas law equation: n = PV / RT

Substitute the given values: n = (2 * 10^5) * 2 / (8.314 * 300.15)

Let's calculate the value of n.