Question

Пожалуйста помогите очень надо) Теплота сгорания суточного рациона питания для школьников вашего возраста составляет около 1,2 МДж. Достаточно ли для вас потребление в течение дня 100 г жирного творога, 50 г пшеничного хлеба,50 г говядины и 200 г картофеля. Необходимые дополнительные данные: Удельная теплота сгорания q*10^3 ,Дж/кг - творог жирный - 9755 - хлеб пшеничный - 9261 - говядина - 7524 - картофель - 3776

Answer 1

Дано:
Q1 = 1.2 МДж
m1 = 100 г = 0.1 кг
m2 = 0.05 кг
m3 = 0.05 кг
m4 = 0.2 кг
q1 = 9.755 * 10^3 Дж/кг
q2 = 9.261 * 10^3 Дж/кг
q3 = 7.524 * 10^3 Дж/кг
q4 = 3.776 * 10^3 Дж/кг
Найти:
Q2 > Q1 или Q2 < Q1 - ?
Решение:
Q2 = m1 * q1 + m2 * q2 + m3 * q3 + m4 * q4 = 0.1 кг * 9755 Дж/кг + 0.05 * 9261 Дж/кг + 0.05 кг * 7524 Дж/кг + 0.2 кг * 3776 Дж/кг = 975.5 Дж + 463.05 Дж + 376.2 Дж + 775.2 Дж = 2569.95 Дж
Q2 < Q1 - нет, не достаточно.
Ответ: Не достаточно.

Answer 2

Calculation of Daily Caloric Intake

To determine if the given daily food ration is sufficient for a person of your age, we need to calculate the total energy content of the food items provided.

Let's calculate the energy content of each food item using the given specific heat of combustion values:

- Fat Cottage Cheese (Tvorog): Specific heat of combustion = 9755 kJ/kg - Wheat Bread (Pshenichnyi Khleb): Specific heat of combustion = 9261 kJ/kg - Beef (Govyadina): Specific heat of combustion = 7524 kJ/kg - Potatoes (Kartofel): Specific heat of combustion = 3776 kJ/kg

Now, let's calculate the energy content of each food item in the given quantities:

- Fat Cottage Cheese (Tvorog): 100 g - Wheat Bread (Pshenichnyi Khleb): 50 g - Beef (Govyadina): 50 g - Potatoes (Kartofel): 200 g

Calculation of Energy Content

1. Fat Cottage Cheese (Tvorog): - Energy content = (Specific heat of combustion * Mass) / 1000 - Energy content = (9755 * 100) / 1000 = 975.5 kJ

2. Wheat Bread (Pshenichnyi Khleb): - Energy content = (Specific heat of combustion * Mass) / 1000 - Energy content = (9261 * 50) / 1000 = 463.05 kJ

3. Beef (Govyadina): - Energy content = (Specific heat of combustion * Mass) / 1000 - Energy content = (7524 * 50) / 1000 = 376.2 kJ

4. Potatoes (Kartofel): - Energy content = (Specific heat of combustion * Mass) / 1000 - Energy content = (3776 * 200) / 1000 = 755.2 kJ

Total Energy Content

Now, let's calculate the total energy content of the given food items:

- Total energy content = Energy content of Fat Cottage Cheese + Energy content of Wheat Bread + Energy content of Beef + Energy content of Potatoes - Total energy content = 975.5 kJ + 463.05 kJ + 376.2 kJ + 755.2 kJ = 2570.95 kJ

The total energy content of the given food items is approximately 2570.95 kJ.

Comparison with Daily Caloric Intake

The given daily caloric intake for schoolchildren of your age is approximately 1.2 MJ (1200 kJ).

Since the total energy content of the given food items is 2570.95 kJ, it is more than sufficient to meet the daily caloric intake requirement.

Therefore, consuming 100 g of fat cottage cheese, 50 g of wheat bread, 50 g of beef, and 200 g of potatoes throughout the day would provide more than enough energy for a person of your age.

Please note that this calculation is based on the given specific heat of combustion values and assumes that the energy content of the food items is solely derived from their combustion. Other factors, such as the body's metabolic efficiency, nutrient absorption, and individual dietary requirements, may also affect the overall energy balance.