Question

Какая работа совершается при ударе кузнечного молота массой 1200 кг, если скорость вначале удара 6 м/c ?

Answer 1

7200 Дж  или 7,2кДж  или  7,2*10^3

Answer 2

Calculating the Work Done by a 1200 kg Hammer Striking at 6 m/s

When a 1200 kg hammer strikes with an initial velocity of 6 m/s, the work done can be calculated using the kinetic energy formula. The work done is equal to the change in kinetic energy of the hammer during the strike.

The formula for kinetic energy is given by:

Kinetic Energy (KE) = 0.5 * mass * velocity^2

Substituting the given values: - Mass (m) = 1200 kg - Initial velocity (v) = 6 m/s

The kinetic energy (KE) of the hammer can be calculated using the formula above. The work done by the hammer during the strike is equal to the change in kinetic energy.

The work done can be calculated using the following steps: 1. Calculate the initial kinetic energy (KE_initial) using the given mass and velocity. 2. After the strike, the hammer comes to rest, so the final kinetic energy (KE_final) is 0. 3. The work done is the change in kinetic energy, which is equal to the initial kinetic energy.

Let's calculate the work done by the hammer using the given values.

Calculations: 1. Initial Kinetic Energy (KE_initial) = 0.5 * 1200 kg * (6 m/s)^2 2. Final Kinetic Energy (KE_final) = 0 (as the hammer comes to rest) 3. Work Done = Change in Kinetic Energy = KE_initial - KE_final

Results: - Initial Kinetic Energy (KE_initial) = 21,600 J - Final Kinetic Energy (KE_final) = 0 J - Work Done = 21,600 J

Therefore, the work done by the 1200 kg hammer striking at 6 m/s is 21,600 joules.

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