Question

Автомобиль,двигаясь с места равноускоренно,прошел участок пути 100 метров за 5 с.Определите ускорение и среднюю скорость автомобиля на этом участке пути

Answer 1

Vср=S/t=100/5=20м/с
S=V0t+(at^2)/2
100=0+(a*25)/2
100=(25a)/2
100=12,5a
a=8м/с^2

Answer 2

Calculation of Acceleration and Average Speed

To determine the acceleration and average speed of the car on this section of the road, we can use the formula:

Acceleration (a) = Change in Velocity (Δv) / Time (t)

Average Speed (v_avg) = Total Distance (d) / Time (t)

Given that the car traveled a distance of 100 meters in 5 seconds, we can calculate the acceleration and average speed using the provided formula.

Calculation:

Acceleration (a) = Change in Velocity (Δv) / Time (t)

Since the car is moving with constant acceleration, we can assume that the initial velocity (u) is 0 m/s.

The final velocity (v) can be calculated using the formula:

v = u + a * t

where: - u = initial velocity (0 m/s) - a = acceleration (to be determined) - t = time (5 seconds)

Substituting the values into the formula, we get:

v = 0 + a * 5

Simplifying the equation, we have:

v = 5a

Given that the car traveled a distance of 100 meters, we can use the formula for average speed:

Average Speed (v_avg) = Total Distance (d) / Time (t)

Substituting the values into the formula, we get:

v_avg = 100 / 5

Simplifying the equation, we have:

v_avg = 20

Now, we can solve for the acceleration (a) by substituting the value of v_avg into the equation v = 5a:

20 = 5a

Simplifying the equation, we have:

a = 4 m/s^2

Therefore, the acceleration of the car on this section of the road is 4 m/s^2 and the average speed is 20 m/s.