Question

Рычаг на который помещен мышонок весом 1 н и слон весом 25000 н находится в равновесии. плечо силы рычага на которое действует слон равно 10 м. какова длина плеча силы на которое действует мышонок? С решением пожалуста.

Answer 1

F2/F1=L1/L2
F2*L2=F1*L1
L1=(F2*L2)/F1
L1=(25000*10)/1=250000м

Answer 2

Calculation of the Length of the Force Arm for the Mouse

To find the length of the force arm on which the mouse acts, we can use the principle of equilibrium. In this case, the force exerted by the elephant (25000 N) and the force exerted by the mouse (1 N) are balanced, resulting in a state of equilibrium.

Let's denote the length of the force arm on which the elephant acts as l1 and the length of the force arm on which the mouse acts as l2.

According to the principle of equilibrium, the product of the force and the length of the force arm should be the same for both the elephant and the mouse. Mathematically, this can be expressed as:

Force of the elephant * Length of the force arm for the elephant = Force of the mouse * Length of the force arm for the mouse

Given that the force of the elephant is 25000 N, the length of the force arm for the elephant is 10 m, and the force of the mouse is 1 N, we can solve for the length of the force arm for the mouse (l2).

Using the equation:

25000 N * 10 m = 1 N * l2

Simplifying the equation:

250000 N*m = l2

Therefore, the length of the force arm on which the mouse acts (l2) is 250000 N*m.

Please let me know if you need any further assistance!