
Мальчик массой 22 килограмма Бегущий со скоростью 2,5 метров секунду, вскакивает сзади на платформу
массой 12 килограмм чему равна результирующая скорость платформы с мальчиком

Ответы на вопрос

m1=22кг
V1=2.5м/с
m2=12кг
v2=0
u-? иЗ закона сохранения m1V1+m2V2=(m1+m2)U; U = m1V1/(m1+m2)
U=22*2.5/34=1.62м/с



Calculation of Resultant Velocity
To calculate the resultant velocity of the platform with the boy, we can use the principle of conservation of momentum. According to this principle, the total momentum before the boy jumps onto the platform is equal to the total momentum after the jump.
The momentum of an object is given by the product of its mass and velocity. Therefore, we can calculate the momentum of the boy and the platform separately before and after the jump, and equate them to find the resultant velocity.
Let's denote: - Mass of the boy = 22 kilograms - Velocity of the boy = 2.5 meters per second - Mass of the platform = 12 kilograms - Resultant velocity of the platform with the boy = v (to be determined)
Conservation of Momentum
Before the jump, the momentum of the boy is given by: Momentum of the boy before = Mass of the boy * Velocity of the boy
After the jump, the momentum of the boy and the platform combined is given by: Momentum of the boy and platform after = (Mass of the boy + Mass of the platform) * Resultant velocity of the platform with the boy
According to the principle of conservation of momentum, we can equate these two expressions:
Mass of the boy * Velocity of the boy = (Mass of the boy + Mass of the platform) * Resultant velocity of the platform with the boy
Calculation
Let's substitute the given values into the equation and solve for the resultant velocity:
22 kg * 2.5 m/s = (22 kg + 12 kg) * v
55 kg * m/s = 34 kg * v
v = (55 kg * m/s) / 34 kg
v ≈ 1.618 m/s
Therefore, the resultant velocity of the platform with the boy is approximately 1.618 meters per second.
Please note that the above calculation assumes an idealized scenario with no external forces acting on the system and neglects factors such as friction.


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