Question

B2 Два резистора с сопротивлениями R1=3Oм R2=6Ом соединены последовательно.Сила тока во втором резисторе I2=2A.Каково общее наряжение U на обоих резисторах?Начертить схему.

Answer 1

Так как они соединены последовательно сила тока для всех резисторов будет одинакова и будет равняться 2 А
U1=I/R1 = 2/3 В
U2=I/R2 = 2/6 В
U(общее) = 2/3 + 2/6 = 4+2/6 = 6/6 = 1 В 

Answer 2

Calculation of Total Voltage and Circuit Diagram

To calculate the total voltage across both resistors, we can use the formula for the total voltage in a series circuit, which is the sum of the voltages across each individual resistor.

The total voltage U across both resistors can be calculated using the formula: U = I1 * R1 + I2 * R2

Where: - U is the total voltage across both resistors - I1 is the current through the first resistor - R1 is the resistance of the first resistor - I2 is the current through the second resistor - R2 is the resistance of the second resistor

Given: - R1 = 3Ω - R2 = 6Ω - I2 = 2A

Using the given values, we can calculate the total voltage U across both resistors: U = I1 * R1 + I2 * R2

We can also represent the circuit diagram for the given scenario. The two resistors, R1 and R2, are connected in series, meaning the current flows through R1 first and then through R2.

Circuit Diagram:

``` ---R1---R2--- | | | | | | --------------- ```

This circuit diagram represents the series connection of the two resistors, R1 and R2.

Let's calculate the total voltage U using the given values.