Question

Силовые линии однородного магнитного поля пересекают площадку в 0,02м под прямым углом. определить модуль вектора индукции магнитного поля если поток магнитной индукции пронизывающий площадку равен 0,04 Вб

Answer 1

Дано S=0,02 м2    Ф=0,04 Вб    B- ?

Ф=B*S
B=Ф/S=0,04/0,02=2 Гн

Ответ L=2 Гн

Answer 2

Calculation of the Magnetic Field Induction

To determine the magnitude of the magnetic field induction vector, we can use the formula:

Φ = B * A * cos(θ)

Where: - Φ is the magnetic flux through the surface area A, - B is the magnitude of the magnetic field induction vector, - A is the surface area, - θ is the angle between the magnetic field induction vector and the normal to the surface.

In this case, the magnetic flux Φ is given as 0.04 Wb, and the angle θ is 90 degrees (since the magnetic field lines intersect the surface at a right angle). The surface area A is not provided in the question.

To find the magnitude of the magnetic field induction vector B, we need to know the surface area A. Unfortunately, the surface area is not given in the question or the search results. Without the surface area, we cannot calculate the magnitude of the magnetic field induction vector B.

Please provide the surface area A so that we can calculate the magnitude of the magnetic field induction vector B.