Question

Шарик скатывается по желобу длиной 125 смс ускорением 1,6м\c² какова скорость шарика в конце желоба? Начальная скорость шарика ыла равна нулю

Answer 1

S=V^2/2a, т.к. Vo=0  откуда V=корень квадратный из(2аS)=
=корень квадратный из(2*1.6*125)=корень квадратный из 400=20[м/с]

Answer 2

Calculation of the Final Velocity of the Ball

To calculate the final velocity of the ball at the end of the chute, we can use the equations of motion. Given that the initial velocity of the ball is zero and the acceleration is 1.6 m/s², we can use the following equation:

v² = u² + 2as

Where: - v is the final velocity - u is the initial velocity (which is zero in this case) - a is the acceleration - s is the distance traveled

In this case, the distance traveled is the length of the chute, which is 125 cm or 1.25 m. Plugging in the values, we get:

v² = 0 + 2 * 1.6 * 1.25

Simplifying the equation, we have:

v² = 4 * 1.25

v² = 5

Taking the square root of both sides, we find:

v = √5

Therefore, the final velocity of the ball at the end of the chute is approximately 2.24 m/s.