Question

При увеличении в 2 раза энергии фотонов, падающих на металлическую пластинку, максимальная кинетическая энергия вылетающих электронов увеличилась в 3 раза. Определить в электронвольтах работу выхода электронов, если первоначальная энергия фотонов 10 эВ. Помогите пожалуйста!

Answer 1

Kmax = E - Aout

Aout = E - Kmax = const

10 эВ  - K1 = 20 эВ - 3K1
2K1 = 10 эВ
К1 = 5 эВ

Aout = E1 - K1 = 10 эВ - 5 эВ = 5 эВ

Answer 2

Calculation of the Work Function in Electron Volts

To determine the work function of the electrons, we can use the given information about the increase in energy of the photons and the corresponding increase in the maximum kinetic energy of the emitted electrons.

According to the problem statement, when the energy of the photons incident on the metallic plate is doubled, the maximum kinetic energy of the emitted electrons increases by a factor of 3.

Let's denote the initial energy of the photons as E1 = 10 eV and the final energy as E2. We need to find the work function, which is the energy required to remove an electron from the metal.

Using the given information, we can set up the following equation:

E2 = E1 * 2 (since the energy of the photons is doubled) E_max2 = E_max1 * 3 (since the maximum kinetic energy of the electrons increases by a factor of 3)

To find the work function, we can use the equation:

Work Function = E1 - E_max1

Substituting the values, we have:

Work Function = 10 eV - E_max1

Now, let's solve for E_max1:

E_max1 = E1 - Work Function

Since E_max2 = E_max1 * 3, we can substitute the value of E_max1:

E_max2 = (E1 - Work Function) * 3

Simplifying the equation:

E_max2 = 3E1 - 3 * Work Function

Now, we can solve for the work function:

Work Function = (3E1 - E_max2) / 3

Substituting the value of E1 = 10 eV:

Work Function = (3 * 10 eV - E_max2) / 3

Therefore, the work function in electron volts is given by (3 * 10 eV - E_max2) / 3.

Please note that we don't have the specific value of E_max2, so we cannot provide the exact numerical value of the work function. However, you can substitute the value of E_max2 into the equation to calculate the work function in electron volts.