Question

Дана цепь: Источник тока=> R1=> R2иR3(между собой соединены параллельно) ЭДС 12в R1=2 ом R2=15 R3=30 Найти I3, P2 Помогите подробным решением пожалуйста

Answer 1

E=12 B    R1=2    R2=15   R3=30   I3=?  P2=?

Общее сопротивление R2 и R3

R23=R2*R3/(R2+R3)=15*30/(15+30)=10 Ом

Общее сопротивление цепи

Ro=R1+R23=2+10=12 Ом

Общий ток цепи

 Io=E/Ro=12/12=1 A

Напряжение на участке R2-R3

U23=Io*R23=1*10=10 B

Ток на сопротивлении I3

I3=U23/R3=10/30=0.3 A

Ток на сопротивлении R2    I2=Io-I23=1-0.3=0.7 A

Мощность сопротивления R2    P2=I2*U23=0.7*10=7 Вт

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Answer 2

Calculation of I3:

To find the current flowing through resistor R3 (I3), we can use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R) of the resistor. Mathematically, it can be represented as:

I = V / R

In this case, the voltage across R3 is the same as the total voltage of the circuit, which is 12V. The resistance of R3 is given as 30 ohms. Plugging these values into the formula, we can calculate I3:

I3 = 12V / 30Ω

Calculating this expression gives us the value of I3 as 0.4 Amperes.

Calculation of P2:

To find the power dissipated by resistor R2 (P2), we can use the formula:

P = I^2 * R

In this case, we already know the current flowing through R2, which is the same as the current flowing through R3 (I3) since they are connected in parallel. We calculated I3 to be 0.4 Amperes. The resistance of R2 is given as 15 ohms. Plugging these values into the formula, we can calculate P2:

P2 = (0.4A)^2 * 15Ω

Calculating this expression gives us the value of P2 as 2.4 Watts.

Therefore, the current flowing through resistor R3 (I3) is 0.4 Amperes, and the power dissipated by resistor R2 (P2) is 2.4 Watts.