Question

В однородном магнитном поле с индукцией 0,8 Тл на проводник с током 30 А, длина активной части которого 10 см, действует сила 1,5 Н. под каким углом к вектору магнитной индукции размещен проводник?

Answer 1

Используй закон Ампера 
F=B*I*L*sin(alpha) 
sin(alpha)=F/(B*I*L) 
alpha=arcsin(F/(B*I*L)) 
не забудь все единицы перевести в систему СИ 

Answer 2

Calculation of the Angle

To determine the angle at which the conductor is placed with respect to the magnetic induction vector, we can use the formula:

F = BILsinθ

Where: - F is the force acting on the conductor (given as 1.5 N) - B is the magnetic induction (given as 0.8 T) - I is the current flowing through the conductor (given as 30 A) - L is the length of the active part of the conductor (given as 10 cm or 0.1 m) - θ is the angle between the conductor and the magnetic induction vector (to be determined)

Rearranging the formula, we have:

sinθ = F / (BIL)

Substituting the given values, we get:

sinθ = 1.5 N / (0.8 T * 30 A * 0.1 m)

Calculating the value, we find:

sinθ ≈ 0.625

To find the angle θ, we can take the inverse sine (arcsin) of 0.625:

θ ≈ arcsin(0.625)

Using a calculator, we find:

θ ≈ 38.7 degrees

Therefore, the conductor is placed at an angle of approximately 38.7 degrees with respect to the magnetic induction vector.